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X^2+36X-832=0
a = 1; b = 36; c = -832;
Δ = b2-4ac
Δ = 362-4·1·(-832)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-68}{2*1}=\frac{-104}{2} =-52 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+68}{2*1}=\frac{32}{2} =16 $
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